JEE MAIN - Chemistry (2025 - 23rd January Morning Shift - No. 15)

Match the List - I with List - II

List - I
Name reaction
List - II
Product obtainable
(A) Swarts reaction (I) Ethyl benzene
(B) Sandmeyer's reaction (II) Ethyl iodide
(C) Wurtz Fittig reaction (III) Cyanobenzene
(D) Finkelstein reaction (IV) Ethyl fluoride

Choose the correct answer from the options given below:

A-II, B-III, C-I, D-IV
A-II, B-I, C-III, D-IV
A-IV, B-I, C-III, D-II
A-IV, B-III, C-I, D-II

Explanation

LIST-i
Name reaction
LIST-II
Product obtainable
(A) Swarts reaction (I) $\mathrm{Et}-\mathrm{I} \xrightarrow[\mathrm{DMF}]{\mathrm{KF}} \mathrm{Et}-\mathrm{F}$
(B) Sandmeyer's reaction (II) $\mathrm{PhN}_2^{\oplus} \mathrm{Cl}^{-} \xrightarrow{\mathrm{CuCN} / \mathrm{KCN}} \mathrm{PhCN}+\mathrm{N}_2$
(C) Wurtz Fittig reaction (III) $$
\mathrm{Ph}-\mathrm{Cl}+\mathrm{EtCl} \xrightarrow[\text { ether }]{\mathrm{Na}}
$$
$$
\mathrm{Ph}-\mathrm{Et}+\mathrm{Ph}-\mathrm{Ph}+\mathrm{Et}-\mathrm{Et}
$$
(D) Finkelstein reaction (IV) $\mathrm{Et}-\mathrm{Cl} \xrightarrow[\text { acetone }]{\mathrm{NaI}} \mathrm{Et}-\mathrm{I}+\mathrm{NaCl}$

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