JEE MAIN - Chemistry (2024 - 9th April Morning Shift - No. 4)
$$0.05 \mathrm{M} \mathrm{~CuSO}_4$$ when treated with $$0.01 \mathrm{M} \mathrm{~K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ gives green colour solution of $$\mathrm{Cu}_2 \mathrm{Cr}_2 \mathrm{O}_7$$. The two solutions are separated as shown below : [SPM : Semi Permeable Membrane]
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Due to osmosis :
Molarity of $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ solution is lowered.
Green colour formation observed on side Y.
Molarity of $$\mathrm{CuSO}_4$$ solution is lowered.
Green colour formation observed on side X.
Explanation
Osmosis leads to the net movement of water molecule from low osmotic pressure to high osmotic pressure. Since the iM value of $$0.05 \mathrm{~M} \mathrm{~CuSO}_4$$ solution is higher hence it has higher osmotic pressure so the water moves towards $$\mathrm{CuSO}_4$$ solution leads to drop of its molarity. The solute molecules do not cross S.P.M. via osmosis.
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