JEE MAIN - Chemistry (2024 - 9th April Evening Shift - No. 3)
Match List I with List II
LIST I (Element) |
LIST II (Electronic Configuration) |
||
---|---|---|---|
A. | $$\mathrm{N}$$ | I. | $$[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^5$$ |
B. | $$\mathrm{S}$$ | II. | $$[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^4$$ |
C. | $$\mathrm{Br}$$ | III. | $$[\mathrm{He}] 2 \mathrm{~s}^2 2 \mathrm{p}^3$$ |
D. | $$\mathrm{Kr}$$ | IV. | $$[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^6$$ |
Choose the correct answer from the options given below:
A-IV, B-III, C-II, D-I
A-I, B-IV, C-III, D-II
A-III, B-II, C-I, D-IV
A-II, B-I, C-IV, D-III
Explanation
To match each element with its correct electronic configuration, let's consider the electronic configurations of each element based on their positions in the periodic table:
- Nitrogen (N): It is in the 2nd period and belongs to the p-block, specifically group 15. The electronic configuration of nitrogen is $$1\text{s}^2 2\text{s}^2 2\text{p}^3$$. Looking at the options in List II, this matches with the electronic configuration labeled 'III' ($$[\mathrm{He}] 2 \mathrm{s}^2 2 \mathrm{p}^3$$), which reflects the electronic configuration of nitrogen starting after the helium core.
- Sulfur (S): Sulfur is in the 3rd period, also in the p-block, specifically group 16. Its electronic configuration is $$1\text{s}^2 2\text{s}^2 2\text{p}^6 3\text{s}^2 3\text{p}^4$$. In the given list, this corresponds to 'II' ($$[\mathrm{Ne}] 3 \mathrm{s}^2 3 \mathrm{p}^4$$), which captures the configuration of sulfur starting after the neon core.
- Bromine (Br): Bromine is located in the 4th period and in the p-block, belonging to group 17. Its electronic configuration is $$1\text{s}^2 2\text{s}^2 2\text{p}^6 3\text{s}^2 3\text{p}^6 3\text{d}^{10} 4\text{s}^2 4\text{p}^5$$, which is correctly represented by 'I' ($$[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^5$$), showing the configuration after the argon core.
- Krypton (Kr): Krypton falls in the 4th period and is a noble gas situated in the p-block at group 18. Its electronic configuration is $$1\text{s}^2 2\text{s}^2 2\text{p}^6 3\text{s}^2 3\text{p}^6 3\text{d}^{10} 4\text{s}^2 4\text{p}^6$$, which aligns with 'IV' ($$[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^6$$), clearly depicting krypton's electronic configuration post-argon.
Therefore, the correct match is:
- A-III (Nitrogen matches with $$[\mathrm{He}] 2 \mathrm{s}^2 2 \mathrm{p}^3$$)
- B-II (Sulfur matches with $$[\mathrm{Ne}] 3 \mathrm{s}^2 3 \mathrm{p}^4$$)
- C-I (Bromine matches with $$[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^5$$)
- D-IV (Krypton matches with $$[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^6$$)
Thus, the correct answer is Option C: A-III, B-II, C-I, D-IV.
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