JEE MAIN - Chemistry (2024 - 9th April Evening Shift - No. 13)
The correct increasing order for bond angles among $$\mathrm{BF}_3, \mathrm{PF}_3$$ and $$\mathrm{ClF}_3$$ is :
$$\mathrm{BF}_3=\mathrm{PF}_3<\mathrm{ClF}_3$$
$$\mathrm{BF}_3<\mathrm{PF}_3<\mathrm{ClF}_3$$
$$\mathrm{ClF}_3<\mathrm{PF}_3<\mathrm{BF}_3$$
$$\mathrm{PF}_3<\mathrm{BF}_3<\mathrm{ClF}_3$$
Explanation
_9th_April_Evening_Shift_en_13_1.png)
Order of bond angle is
$$\mathrm{ClF}_3<\mathrm{PF}_3<\mathrm{BF}_3$$
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