JEE MAIN - Chemistry (2024 - 8th April Morning Shift - No. 24)
A hypothetical electromagnetic wave is show below.
_8th_April_Morning_Shift_en_24_1.png)
The frequency of the wave is $$\mathrm{x} \times 10^{19} \mathrm{~Hz}$$.
$$\mathrm{x}=$$ _________ (nearest integer)
Answer
5
Explanation
$$\begin{aligned}
\lambda & =1.5 \times 4=6 \mathrm{~pm} \\
\nu & =\frac{C}{\lambda} \\
\nu & =\frac{3 \times 10^8}{6 \times 10^{-12}} \\
& =0.5 \times 10^{20} \\
\nu & =5 \times 10^{19} \\
x & =5
\end{aligned}$$
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