JEE MAIN - Chemistry (2024 - 8th April Morning Shift - No. 21)

If $$279 \mathrm{~g}$$ of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be ________ g. (nearest integer)

(consider complete conversion).

Answer
591

Explanation

JEE Main 2024 (Online) 8th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 22 English Explanation

Mole of aniline $$=\frac{279}{93}=3 \mathrm{~mol}$$

Mole of aniline yellow formed $$=3 \mathrm{~mol}$$

$$\begin{gathered} \text { Mass }=3 \times 197 \\ =591 \mathrm{~g} \end{gathered}$$

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