JEE MAIN - Chemistry (2024 - 8th April Morning Shift - No. 20)

Match List I with List II

	LIST I (Compound)		LIST II (Colour]
A.	$$\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH_2O}$$	I.	Violet
B.	$$\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$$	II.	Blood Red
C.	$$[\mathrm{Fe}(\mathrm{SCN})]^{2+}$$	III.	Prussian Blue
D.	$$\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4\cdot12 \mathrm{MoO}_3$$	IV.	Yellow

Choose the correct answer from the options given below:

A-IV, B-I, C-II, D-III

A-I, B-II, C-III, D-IV

A-II, B-III, C-IV, D-I

A-III, B-I, C-II, D-IV

To match List I with List II correctly, we need to identify the colors associated with each compound.

Let's analyze each compound:

1. $$\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH_2O}$$ - This is known as Prussian Blue.

2. $$\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$$ - This complex is known to have a violet color.

3. $$[\mathrm{Fe}(\mathrm{SCN})]^{2+}$$ - This ion is known for its blood red color.

4. $$\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4\cdot12 \mathrm{MoO}_3$$ - This is commonly known as Ammonium phosphomolybdate, which is yellow.

Matching each item, we get:

	LIST I (Compound)		LIST II (Colour)
A.	$$\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH_2O}$$	III.	Prussian Blue
B.	$$\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$$	I.	Violet
C.	$$[\mathrm{Fe}(\mathrm{SCN})]^{2+}$$	II.	Blood Red
D.	$$\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4\cdot12 \mathrm{MoO}_3$$	IV.	Yellow

Based on the analysis, the correct matching is:

Option D: A-III, B-I, C-II, D-IV