JEE MAIN - Chemistry (2024 - 8th April Evening Shift - No. 29)
Explanation
The wavenumber of a radiation is defined as the number of wavelengths per unit distance and is the reciprocal of the wavelength. Wavenumber is commonly represented in units of $$\mathrm{cm}^{-1}$$.
First, convert the given wavelength from angstroms ($$\mathop A\limits^o $$) to centimeters (cm). We know that:
$$1 \mathop A\limits^o = 10^{-8} \, \text{cm}$$
Given wavelength is 5800 $$\mathop A\limits^o $$:
$$5800 \mathop A\limits^o = 5800 \times 10^{-8} \, \text{cm}$$
Now calculate the wavenumber ($$\tilde{\nu}$$) which is the reciprocal of the wavelength:
$$\tilde{\nu} = \frac{1}{{5800 \times 10^{-8} \, \text{cm}}}$$
Simplify the expression:
$$\tilde{\nu} = \frac{1}{5800 \times 10^{-8} \, \text{cm}} = \frac{10^8}{5800} \, \mathrm{cm}^{-1}$$
Now, divide the numerator by the denominator to calculate the precise value:
$$\tilde{\nu} = \frac{10^8}{5800} \approx 1.724 \times 10^4 \, \mathrm{cm}^{-1}$$
Here, it is given that the wavenumber is in the form of $$x \times 10 \, \mathrm{cm}^{-1}$$, so $$x$$ would be the value we calculated divided by 10:
$$x = \frac{1.724 \times 10^4}{10} = 1724$$
Thus, the integer answer for the value of $$x$$ is:
1724
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