JEE MAIN - Chemistry (2024 - 8th April Evening Shift - No. 16)
Match List I with List II
| LIST I (Test) |
LIST II (Identification) |
||
|---|---|---|---|
| A. | Bayer's test | I. | Phenol |
| B. | Ceric ammonium nitrate test | II. | Aldehyde |
| C. | Phthalein dye test | III. | Alcoholic-OH group |
| D. | Schiff's test | IV. | Unsaturation |
Choose the correct answer from the options given below :
Explanation
To match the tests in List I with the corresponding identifications in List II, let's analyze each test:
Bayer's test: This test is used to test for unsaturation in compounds, such as alkenes and alkynes. The presence of unsaturation is indicated by the decolorization of potassium permanganate solution.
Ceric ammonium nitrate test: This test is used to identify alcohols. A positive result is indicated by a color change.
Phthalein dye test: This test is used to identify phenols. Phenols react with phthalic anhydride to form a colored compound.
Schiff's test: This test is used for the detection of aldehydes. A positive result indicates the formation of a magenta or pink colored compound.
Based on the information above, the correct matching is:
- A. Bayer's test - IV. Unsaturation
- B. Ceric ammonium nitrate test - III. Alcoholic-OH group
- C. Phthalein dye test - I. Phenol
- D. Schiff's test - II. Aldehyde
Thus, the correct answer is:
Option D: (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
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