JEE MAIN - Chemistry (2024 - 6th April Evening Shift - No. 5)
Match List I with List II.
| LIST I Reaction |
LIST II Type of redox reaction |
||
|---|---|---|---|
| A. | $$ \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{NO}_{(\mathrm{g})} $$ |
I. | Decomposition |
| B. | $$ 2 \mathrm{~Pb}\left(\mathrm{NO}_3\right)_{2(\mathrm{~s})} \rightarrow 2 \mathrm{PbO}_{(\mathrm{s})}+4 \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} $$ |
II. | Displacement |
| C. | $$ 2 \mathrm{Na}_{(\mathrm{s})}+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})} \rightarrow 2 \mathrm{NaOH}_{(\mathrm{aq} .)}+\mathrm{H}_{2(\mathrm{~g})} $$ |
III. | Disproportionation |
| D. | $$ 2 \mathrm{NO}_{2(\mathrm{~g})}+2^{-} \mathrm{OH}(\text { aq. }) \rightarrow \mathrm{NO}_{2(\mathrm{aq} .)}^{-}+\mathrm{NO}_{3(\text { aq. })}^{-}+\mathrm{H}_2 \mathrm{O}_{(\mathrm{l})} $$ |
IV. | Combination |
Choose the correct answer from the options given below :
Explanation
(A) $$\stackrel{\circ}{\mathrm{N}}_2+\stackrel{\circ}{\mathrm{O}}_2 \longrightarrow 2 \mathrm{NO}_{(\mathrm{g})}$$
Combination reaction
(B) $$2 \mathrm{~Pb}\left(\mathrm{NO}_3\right)_{2(\mathrm{~s})} \longrightarrow 2 \mathrm{PbO}+4 \mathrm{NO}_2+\mathrm{O}_2$$
Decomposition reaction
(C) $$2 \mathrm{Na}_{(\mathrm{s})}+2 \mathrm{H}_2 \mathrm{O}(\mathrm{I}) \longrightarrow 2 \mathrm{NaOH}_{(\mathrm{aq})}+\mathrm{H}_{2(\mathrm{~g})}$$
Displacement reaction
(D) $$2 \mathrm{NO}_{2(\mathrm{~g})}+2 \mathrm{OH}_{(\mathrm{g})}^{-} \longrightarrow \mathrm{NO}_{2 \text { (aq) }}^{-}+\mathrm{NO}_{3(\text { (qq) }}^{-}+\mathrm{H}_2 \mathrm{O}$$
Nitrogen oxidises and reduces both. So it is a disproportionation reaction.
$$\mathrm{A} \rightarrow(\mathrm{IV}), \mathrm{B} \rightarrow(\mathrm{I}), \mathrm{C} \rightarrow(\mathrm{II}), \mathrm{D} \rightarrow(\mathrm{III})$$
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