JEE MAIN - Chemistry (2024 - 6th April Evening Shift - No. 2)
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The correct arrangement for decreasing order of electrophilic substitution for above compounds is :
$$\text { (III) }>\text { (IV) }>\text { (II) }>\text { (I) }$$
$$\text { (III) }>\text { (I) }>\text { (II) }>\text { (IV) }$$
$$\text { (II) }>\text { (IV) }>\text { (III) }>\text { (I) }$$
$$(\text { IV) }>\text { (I) }>\text { (II) }>\text { (III) }$$
Explanation
Methoxy group strongly activates benzene ring towards electrophilic aromatic substitution due to $$+\mathrm{R}$$ effect. Methyl group weakly activates benzene ring due to its $$+\mathrm{I}$$ and $$+\mathrm{H}$$ effects. $$\mathrm{CF}_3$$ group strongly deactivates the benzene ring due to $$-\mathrm{I}$$ and $$-\mathrm{H}$$ effects.
Therefore, the correct order of the given compounds towards electrophilic aromatic substitution is
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