JEE MAIN - Chemistry (2024 - 6th April Evening Shift - No. 11)
Match List I with List II.
| LIST I Tetrahedral Complex |
LIST II Electronic configuration |
||
|---|---|---|---|
| A. | $$ \mathrm{TiCl}_4 $$ |
I. | $$ \mathrm{e}^2, \mathrm{t}_2^0 $$ |
| B. | $$ \left[\mathrm{FeO}_4\right]^{2-} $$ |
II. | $$ \mathrm{e^4, t_2^3} $$ |
| C. | $$ \left[\mathrm{FeCl}_4\right]^{-} $$ |
III. | $$ \mathrm{e}^0, \mathrm{t}_2^0 $$ |
| D. | $$ \left[\mathrm{CoCl}_4\right]^{2-} $$ |
IV. | $$ \mathrm{e}^2, \mathrm{t}_2^3 $$ |
Choose the correct answer from the options given below :
(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
Explanation
(A) $$\mathrm{TiCl}_4: \mathrm{Ti}^{4+}: 3 d^0 4 s^0$$ or $$\mathrm{e}^0 \mathrm{t}_2^0$$
(B) $$\left[\mathrm{FeO}_4\right]^{2-}: \mathrm{Fe}^{6+}: 3 d^2 4 s^0$$ or $$\mathrm{e}^2 \mathrm{t}_2^0$$
(C) $$\left[\mathrm{FeCl}_4\right]^{-}: \mathrm{Fe}^{3+}: 3 d^5 4 s^0$$ or $$\mathrm{e}^2 \mathrm{t}_2^3$$
(D) $$\left[\mathrm{CoCl}_4\right]^{2-}: \mathrm{Co}^{2+}: 3 d^7 4 s^0$$ or $$\mathrm{e}^4 \mathrm{t}_2^3$$
$$\therefore$$ Correct matching of tetrahedral complexes given in List-I with their electronic configuration given in List-II is
(A)-(III); (B)-(I); (C)-(IV); (D)-(II)
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