JEE MAIN - Chemistry (2024 - 6th April Evening Shift - No. 10)
Given below are two statements :
Statement I : $$\mathrm{PF}_5$$ and $$\mathrm{BrF}_5$$ both exhibit $$\mathrm{sp}^3 \mathrm{~d}$$ hybridisation.
Statement II : Both $$\mathrm{SF}_6$$ and $$[\mathrm{Co}(\mathrm{NH}_3)_6]^{3+}$$ exhibit $$\mathrm{sp}^3 \mathrm{~d}^2$$ hybridisation.
In the light of the above statements, choose the correct answer from the options given below :
Explanation
Hybridisation of $$\mathrm{P}$$ in $$\mathrm{PF}_5$$ is $$s p^3 d$$ but the hybridisation of $$\mathrm{Br}$$ in $$\mathrm{BrF}_5$$ is $$s p^3 d^2$$. So, statement-I is false.
Hybridisation of $$\mathrm{S}$$ in $$\mathrm{SF}_6$$ is $$s p^3 d^2$$ but the hybridisation of $$\mathrm{Co}^{3+}$$ in $$[\mathrm{Co}(\mathrm{NH}_3)_6]^{3+}$$ is $$d^2 s p^3$$ as $$\mathrm{NH}_3$$ is a strong field ligand forcing the unpaired electrons to pair up. So, statement-II is false.
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