JEE MAIN - Chemistry (2024 - 5th April Morning Shift - No. 30)

During Kinetic study of reaction $$\mathrm{2 A+B \rightarrow C+D}$$, the following results were obtained :

$$\mathrm{A [M]}$$ $$\mathrm{B [M]}$$ initial rate of formation of $$\mathrm{D}$$
I 0.1 0.1 $$6.0\times10^{-3}$$
II 0.3 0.2 $$7.2\times10^{-2}$$
III 0.3 0.4 $$2.88\times10^{-1}$$
IV 0.4 0.1 $$2.40\times10^{-2}$$

Based on above data, overall order of the reaction is _________.

Answer
3

Explanation

$$\begin{aligned} & \text { Rate }=k[A]^x[B]^y \\ & \frac{6 \times 10^{-}}{2.4 \times 10^{-}}=\left(\frac{0.1}{0.4}\right)^x \Rightarrow x=1 \\ & \frac{7.2 \times 10^{-}}{2.88 \times 10^{-}}=\left(\frac{0.2}{0.4}\right)^y \Rightarrow y=2 \end{aligned}$$

Comments (0)

Advertisement