JEE MAIN - Chemistry (2024 - 5th April Morning Shift - No. 14)
Which one of the following complexes will exhibit the least paramagnetic behaviour ?
[Atomic number, $$\mathrm{Cr}=24, \mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27$$]
$$\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$$
$$\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$$
$$\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$$
$$\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$$
Explanation
_5th_April_Morning_Shift_en_14_1.png)
So, the complex with minimum number of unpaired $$\mathrm{e}^{\ominus}$$ is option (2) $$\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$$.
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