JEE MAIN - Chemistry (2024 - 5th April Evening Shift - No. 27)
In the Claisen-Schmidt reaction to prepare $$351 \mathrm{~g}$$ of dibenzalacetone using $$87 \mathrm{~g}$$ of acetone, the amount of benzaldehyde required is _________ g. (Nearest integer)
Answer
318
Explanation
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$$\begin{aligned} & \text { mol of benzaldehyde required }=1.5 \times 2 \\ &=3 \mathrm{~mol} \\ & \text { mass }=318 \mathrm{~g} \end{aligned}$$
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