JEE MAIN - Chemistry (2024 - 5th April Evening Shift - No. 17)
Explanation
To determine the quantity of silver deposited when one coulomb of charge is passed through $$\mathrm{AgNO}_3$$ solution, we need to refer to Faraday's laws of electrolysis, especially to the concept of the electrochemical equivalent. The electrochemical equivalent (ECE) of a substance is the amount of the substance that is deposited or dissolved at an electrode during electrolysis by one coulomb of charge.
The electrochemical equivalent of a substance can be calculated using the formula:
$$E = \frac{M}{nF}$$
where:
- $E$ is the electrochemical equivalent of the substance in grams per coulomb ($\mathrm{g/C}$).
- $M$ is the molar mass of the substance in grams per mole ($\mathrm{g/mol}$).
- $n$ is the number of electrons involved in the oxidation or reduction reaction (the valency).
- $F$ is the Faraday constant, approximately $96485 \, \mathrm{C/mol}$, which is the charge of one mole of electrons.
In the case of silver ($\mathrm{Ag}$) being deposited from $ \mathrm{AgNO}_3 $, when silver ion ($\mathrm{Ag}^+$) is reduced to metallic silver ($\mathrm{Ag}$), the reaction involves one electron ($n = 1$). The molar mass of silver (Ag) is approximately $107.868 \, \mathrm{g/mol}$. Using this information:
$$E = \frac{107.868 \, \mathrm{g/mol}}{1 \cdot 96485 \, \mathrm{C/mol}} \approx 0.001118 \, \mathrm{g/C}$$
This means that for every coulomb of charge passed through the solution, $0.001118 \, \mathrm{g}$ of silver is deposited.
Given the options:
- Option A: $0.1$ g atom of silver - This is incorrect because the calculation shows a much smaller amount is deposited per coulomb.
- Option B: 1 chemical equivalent of silver - This does not directly relate to the amount deposited per coulomb.
- Option C: $1 \mathrm{~g}$ of silver - This is incorrect as it overestimates the amount deposited by a large margin.
- Option D: 1 electrochemical equivalent of silver - This is correct, as it directly relates to the amount of a substance deposited by one coulomb of charge, based on the formula and calculation shown.
Therefore, the correct answer is Option D: 1 electrochemical equivalent of silver.
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