JEE MAIN - Chemistry (2024 - 4th April Morning Shift - No. 6)

Identify the correct set of reagents or reaction conditions '$$X$$' and '$$Y$$' in the following set of transformation.

JEE Main 2024 (Online) 4th April Morning Shift Chemistry - Haloalkanes and Haloarenes Question 19 English

$$\mathrm{X}=$$ dil.aq. $$\mathrm{NaOH}, 20^{\circ} \mathrm{C}, \quad \mathrm{Y}=\mathrm{HBr} /$$ acetic acid
$$\mathrm{X}=$$ conc.alc. $$\mathrm{NaOH}, 80^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{Br}_2 / \mathrm{CHCl}_3$$
$$\mathrm{X}=$$ dil.aq. $$\mathrm{NaOH}, 20^{\circ} \mathrm{C}, \quad \mathrm{Y}=\mathrm{Br}_2 / \mathrm{CHCl}_3$$
$$\mathrm{X}=$$ conc.alc. $$\mathrm{NaOH}, 80^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{HBr} /$$ acetic acid

Explanation

JEE Main 2024 (Online) 4th April Morning Shift Chemistry - Haloalkanes and Haloarenes Question 19 English Explanation 1 JEE Main 2024 (Online) 4th April Morning Shift Chemistry - Haloalkanes and Haloarenes Question 19 English Explanation 2

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