JEE MAIN - Chemistry (2024 - 4th April Morning Shift - No. 22)
Only $$2 \mathrm{~mL}$$ of $$\mathrm{KMnO}_4$$ solution of unknown molarity is required to reach the end point of a titration of $$20 \mathrm{~mL}$$ of oxalic acid $$(2 \mathrm{M})$$ in acidic medium. The molarity of $$\mathrm{KMnO}_4$$ solution should be ________ M.
Answer
8
Explanation
$$\begin{aligned}
& \mathrm{(M) \times(2) \times(5)=2 \times 20 \times 2} \\
& \mathrm{M=8}
\end{aligned}
$$
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