JEE MAIN - Chemistry (2024 - 31st January Evening Shift - No. 6)
Given below are two statements:
Statement I : $$\mathrm{S}_8$$ solid undergoes disproportionation reaction under alkaline conditions to form $$\mathrm{S}^{2-}$$ and $$\mathrm{S}_2 \mathrm{O}_3{ }^{2-}$$.
Statement II : $$\mathrm{ClO}_4^{-}$$ can undergo disproportionation reaction under acidic condition.
In the light of the above statements, choose the most appropriate answer from the options given below :
Statement I is correct but statement II is incorrect
Both statement I and statement II are incorrect
Statement I is incorrect but statement II is correct
Both statement I and statement II are correct
Explanation
$$\mathrm{S}_1: \mathrm{S}_8+12 \mathrm{OH}^{\ominus} \rightarrow 4 \mathrm{~S}^{2-}+2 \mathrm{~S}_2 \mathrm{O}_3^{2-}+6 \mathrm{H}_2 \mathrm{O}$$
$$\mathrm{S}_2: \mathrm{ClO}_4^{\ominus}$$ cannot undergo disproportionation reaction as chlorine is present in it's highest oxidation state.
Comments (0)
