JEE MAIN - Chemistry (2024 - 30th January Morning Shift - No. 6)
Compound A formed in the following reaction reacts with B gives the product C. Find out A and B.
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$$\mathrm{A}=\mathrm{CH}_3-\mathrm{C} \equiv \stackrel{-}{\mathrm{C}} \mathrm{Na}^{+}, \mathrm{B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}$$
$$\mathrm{A}=\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2, \mathrm{~B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}$$
$$\mathrm{A}=\mathrm{CH}_3-\mathrm{C} \equiv \stackrel{-}{\mathrm{C}} \mathrm{Na}^{+}, \mathrm{B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3$$
$$\mathrm{A}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3, \mathrm{~B}=\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}$$
Explanation
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