JEE MAIN - Chemistry (2024 - 30th January Morning Shift - No. 3)
Given below are two statements :
Statement (I) : The gas liberated on warming a salt with dil $$\mathrm{H}_2 \mathrm{SO}_4$$, turns a piece of paper dipped in lead acetate into black, it is a confirmatory test for sulphide ion.
Statement (II) : In statement-I the colour of paper turns black because of formation of lead sulphite. In the light of the above statements, choose the most appropriate answer from the options given below :
Both Statement I and Statement II are false
Statement I is true but Statement II is false
Both Statement I and Statement II are true
Statement I is false but Statement II is true
Explanation
$$\mathrm{Na}_2 \mathrm{S}+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{Na}_2 \mathrm{SO}_4+\mathrm{H}_2 \mathrm{S}$$
$$\mathrm{{(C{H_3}COO)_2}Pb + {H_2}S \to \mathop {PbS}\limits_{Black\,lead\,sulphide} + 2C{H_3}COOH}$$
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