JEE MAIN - Chemistry (2024 - 30th January Morning Shift - No. 10)
Match List I with List II.
| List I Species |
List II Electronic distribution |
||
|---|---|---|---|
| (A) | $$\mathrm{Cr^{+2}}$$ | (I) | $$\mathrm{3d^8}$$ |
| (B) | $$\mathrm{Mn^+}$$ | (II) | $$\mathrm{3d^34s^1}$$ |
| (C) | $$\mathrm{Ni^{+2}}$$ | (III) | $$\mathrm{3d^4}$$ |
| (D) | $$\mathrm{V^+}$$ | (IV) | $$\mathrm{3d^54s^1}$$ |
Choose the correct answer from the options given below :
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Explanation
$$\begin{gathered}
{ }_{24} \mathrm{Cr} \rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^5 4 \mathrm{~s}^1 ; \mathrm{Cr}^{2+} \rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^4 \\
{ }_{25} \mathrm{Mn} \rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^5 4 \mathrm{s}^2 ; \mathrm{Mn}^{+} \rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^5 4 \mathrm{s}^1 \\
{ }_{28} \mathrm{Ni} \rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^8 4 \mathrm{s}^2 ; \mathrm{Ni}^{2+} \rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^8 \\
{ }_{23} \mathrm{V} \rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^3 4 \mathrm{s}^2 ; \mathrm{V}^{+} \rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^3 4 \mathrm{s}^1
\end{gathered}$$
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