JEE MAIN - Chemistry (2024 - 30th January Evening Shift - No. 17)
The orange colour of $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ and purple colour of $$\mathrm{KMnO}_4$$ is due to
Charge transfer transition in both.
$$\mathrm{d} \rightarrow \mathrm{d}$$ transitions in $$\mathrm{KMnO}_4$$ and charge transfer transitions in $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$.
$$\mathrm{d} \rightarrow \mathrm{d}$$ transitions in both
$$\mathrm{d} \rightarrow \mathrm{d}$$ transitions in $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ and charge transfer transitions in $$\mathrm{KMnO}_4$$.
Explanation
$$\left.\begin{array}{l}
\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 \rightarrow \mathrm{Cr}^{+6} \rightarrow \text { No d - d transition } \\
\mathrm{KMnO}_4 \rightarrow \mathrm{Mn}^{7+} \rightarrow \text { No d - d transition }
\end{array}\right\} \text { Charge transfer }$$
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