JEE MAIN - Chemistry (2024 - 30th January Evening Shift - No. 15)

m-chlorobenzaldehyde on treatment with 50% KOH solution yields :
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 33 English Option 1
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 33 English Option 2
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 33 English Option 3
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 33 English Option 4

Explanation

Meta-chlorobenzaldehyde will undergo

Cannizzaro reaction with $$50 \% \mathrm{~KOH}$$ to give $$\mathrm{m}-$$ chlorobenzoate ion and m-chlorobenzyl alcohol.

JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 33 English Explanation

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