JEE MAIN - Chemistry (2024 - 29th January Morning Shift - No. 17)
$$\mathrm{KMnO}_4$$ decomposes on heating at $$513 \mathrm{~K}$$ to form $$\mathrm{O}_2$$ along with
$$\mathrm{K}_2 \mathrm{MnO}_4 ~\& \mathrm{~Mn}$$
$$\mathrm{MnO}_2 ~\& \mathrm{~K}_2 \mathrm{O}_2$$
$$\mathrm{K}_2 \mathrm{MnO}_4 ~\& \mathrm{~MnO}_2$$
$$\mathrm{Mn} ~\& \mathrm{~KO}_2$$
Explanation
$$\mathrm{KMnO}_4 \xrightarrow{\Delta} \mathrm{K}_2 \mathrm{MnO}_4+\mathrm{MnO}_2+\mathrm{O}_2$$
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