JEE MAIN - Chemistry (2024 - 29th January Evening Shift - No. 30)
Molality of 0.8 M H$$_2$$SO$$_4$$ solution (density 1.06 g cm$$^{-3}$$) is ________ $$\times10^{-3}$$ m.
Answer
815
Explanation
$$\mathrm{m}=\frac{\mathrm{M} \times 1000}{\mathrm{~d}_{\text {sol }} \times 1000-\mathrm{M} \times \text { Molar mass }_{\text {solute }}}$$
$$815 \times 10^{-3} \mathrm{~m}$$
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