JEE MAIN - Chemistry (2024 - 29th January Evening Shift - No. 13)
Which of the following reaction is correct?
$$\mathrm{C}_2 \mathrm{H}_5 \mathrm{CONH}_2+\mathrm{Br}_2+\mathrm{NaOH} \rightarrow \mathrm{C}_2 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{NH}_2+\mathrm{Na}_2 \mathrm{CO}_3+\mathrm{NaBr}+\mathrm{H}_2 \mathrm{O}$$
_29th_January_Evening_Shift_en_13_1.png)
_29th_January_Evening_Shift_en_13_2.png)
$$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2 \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\mathrm{HNO}_2, 0^{\circ} \mathrm{C}} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}+\mathrm{N}_2+\mathrm{HCl}$$
Explanation
The correct organic products of given reactions are as follows
1. $\mathrm{C}_2 \mathrm{H}_5 \mathrm{CONH}_2+\mathrm{Br}_2+\mathrm{NaOH} \rightarrow \mathrm{C}_2 \mathrm{H}_5 \mathrm{NH}_2$
2. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2 \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\mathrm{HNO}_2, 0^{\circ} \mathrm{C}} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{OH}$
_29th_January_Evening_Shift_en_13_3.png)
1. $\mathrm{C}_2 \mathrm{H}_5 \mathrm{CONH}_2+\mathrm{Br}_2+\mathrm{NaOH} \rightarrow \mathrm{C}_2 \mathrm{H}_5 \mathrm{NH}_2$
2. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2 \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\mathrm{HNO}_2, 0^{\circ} \mathrm{C}} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{OH}$
Comments (0)
