JEE MAIN - Chemistry (2024 - 29th January Evening Shift - No. 10)
The correct IUPAC name of $$\mathrm{K}_2 \mathrm{MnO}_4$$ is
Potassium tetraoxidomanganate (VI)
Dipotassium tetraoxidomanganate (VII)
Potassium tetraoxopermanganate (VI)
Potassium tetraoxidomanganese (VI)
Explanation
$$\begin{aligned} & \mathrm{K}_2 \mathrm{MnO}_4 \\ & 2+\mathrm{x}-8=0 \\ & \Rightarrow \mathrm{x}=+6 \end{aligned}$$
$$\mathrm{O.S.}$$ of $$\mathrm{Mn}=+6$$
IUPAC Name $$=$$
Potassium tetraoxidomanganate(VI)
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