JEE MAIN - Chemistry (2024 - 29th January Evening Shift - No. 1)
On passing a gas, '$$\mathrm{X}$$', through Nessler's regent, a brown precipitate is obtained. The gas '$$\mathrm{X}$$' is
$$\mathrm{Cl}_2$$
$$\mathrm{CO}_2$$
$$\mathrm{NH}_3$$
$$\mathrm{H}_2 \mathrm{S}$$
Explanation
Nessler's Reagent Reaction :
$$\underset{\text { (Nessler's Reagent) }}{2 \mathrm{~K}_2 \mathrm{HgI}_4}+\mathrm{NH}_3+3 \mathrm{KOH} \rightarrow \underset{\substack{\text { (lodine of Millon's base } \\ \text { (Brown precipitate }}}{\mathrm{HgO} . \mathrm{Hg}\left(\mathrm{NH}_2\right) \mathrm{I}}+7 \mathrm{KI}+2 \mathrm{H}_2 \mathrm{O}$$
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