JEE MAIN - Chemistry (2024 - 27th January Morning Shift - No. 18)

$$\mathrm{NaCl}$$ reacts with conc. $$\mathrm{H}_2 \mathrm{SO}_4$$ and $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ to give reddish fumes (B), which react with $$\mathrm{NaOH}$$ to give yellow solution (C). (B) and (C) respectively are ;
$$\mathrm{CrO}_2 \mathrm{Cl}_2, \mathrm{Na}_2 \mathrm{CrO}_4$$
$$\mathrm{Na}_2 \mathrm{CrO}_4, \mathrm{CrO}_2 \mathrm{Cl}_2$$
$$\mathrm{CrO}_2 \mathrm{Cl}_2, \mathrm{KHSO}_4$$
$$\mathrm{CrO}_2 \mathrm{Cl}_2, \mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_7$$

Explanation

JEE Main 2024 (Online) 27th January Morning Shift Chemistry - d and f Block Elements Question 46 English Explanation

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