JEE MAIN - Chemistry (2024 - 27th January Evening Shift - No. 7)
Identify B formed in the reaction.
$$\mathrm{Cl}-\left(\mathrm{CH}_2\right)_4-\mathrm{Cl} \xrightarrow{\text { excess } \mathrm{NH}_3} \mathrm{~A} \xrightarrow{\mathrm{NaOH}} \mathrm{B}+\mathrm{H}_2 \mathrm{O}+\mathrm{NaCl}$$
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$$\stackrel{-}{\mathrm{Cl}}\stackrel{+}{\mathrm{N}} \mathrm{H}_3-\left(\mathrm{CH}_2\right)_4-\stackrel{+}{\mathrm{N}} \mathrm{H}_3 \mathrm{Cl}^{-}$$
$$\mathrm{H}_2 \mathrm{N}-\left(\mathrm{CH}_2\right)_4-\mathrm{NH}_2$$
Explanation
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