JEE MAIN - Chemistry (2024 - 27th January Evening Shift - No. 22)
The Spin only magnetic moment value of square planar complex $$\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}\left(\mathrm{NH}_2 \mathrm{CH}_3\right)\right] \mathrm{Cl}$$ is _________ B.M. (Nearest integer)
(Given atomic number for $$\mathrm{Pt}=78$$)
Answer
0
Explanation
$$\mathrm{Pt^2+ (d^8)}$$
_27th_January_Evening_Shift_en_22_1.png)
$$\mathrm{Pt}^{2+} \rightarrow \mathrm{dsp}^2$$ hybridization and have no unpaired $$\mathrm{e}^{-} \mathrm{s}$$.
$$\therefore$$ Magnetic moment $$=0$$
Comments (0)
