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JEE MAIN - Chemistry (2024 - 27th January Evening Shift - No. 20)

The molecular formula of second homologue in the homologous series of mono carboxylic acids is
$$\mathrm{C}_2 \mathrm{H}_4 \mathrm{O}_2$$
$$\mathrm{C}_2 \mathrm{H}_2 \mathrm{O}_2$$
$$\mathrm{CH}_2 \mathrm{O}$$
$$\mathrm{C}_3 \mathrm{H}_6 \mathrm{O}_2$$

Explanation

JEE Main 2024 (Online) 27th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 41 English Explanation

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