JEE MAIN - Chemistry (2024 - 27th January Evening Shift - No. 17)
The final product A, formed in the following reaction sequence is:
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$$\mathrm{Ph}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH}$$
$$\mathrm{Ph}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_3$$
Explanation
$$\mathrm{PhCH}=\mathrm{CH}_2 \xrightarrow{\mathrm{B}_2 \mathrm{H}_6 / \mathrm{H}_2 \mathrm{O}_2 \mathrm{OH}^{-}} \mathrm{PhCH}_2 \mathrm{CH}_2 \mathrm{OH}$$
_27th_January_Evening_Shift_en_17_4.png)
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