JEE MAIN - Chemistry (2024 - 27th January Evening Shift - No. 15)
Choose the correct option having all the elements with $$\mathrm{d}^{10}$$ electronic configuration from the following :
$${ }^{46} \mathrm{Pd},{ }^{28} \mathrm{Ni},{ }^{26} \mathrm{Fe},{ }^{24} \mathrm{Cr}$$
$${ }^{29} \mathrm{Cu},{ }^{30} \mathrm{Zn},{ }^{48} \mathrm{Cd},{ }^{47} \mathrm{Ag}$$
$${ }^{27} \mathrm{Co},{ }^{28} \mathrm{Ni},{ }^{26} \mathrm{Fe},{ }^{24} \mathrm{Cr}$$
$${ }^{28} \mathrm{Ni},{ }^{24} \mathrm{Cr},{ }^{26} \mathrm{Fe},{ }^{29} \mathrm{Cu}$$
Explanation
$$\begin{aligned}
& {[\mathrm{Cr}]=[\mathrm{Ar}] 4 \mathrm{~s}^1 3 \mathrm{~d}^5} \\
& {[\mathrm{Cd}]=[\mathrm{Kr}] 5 \mathrm{~s}^2 4 \mathrm{~d}^{10}} \\
& {[\mathrm{Cu}]=[\mathrm{Ar}] 4 \mathrm{~s}^1 3 \mathrm{~d}^{10}} \\
& {[\mathrm{Ag}]=[\mathrm{Kr}] 5 \mathrm{~s}^1 4 \mathrm{~d}^{10}} \\
& {[\mathrm{Zn}]=[\mathrm{Ar}] 4 \mathrm{~s}^2 3 \mathrm{~d}^{10}}
\end{aligned}$$
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