JEE MAIN - Chemistry (2024 - 27th January Evening Shift - No. 10)
Match List - I with List - II.
| List - I (Reaction) |
List - II (Reagent(s)) |
||
|---|---|---|---|
| (A) | _27th_January_Evening_Shift_en_10_1.png) |
(I) | $$\mathrm{Na_2Cr_2O_7,H_2SO_4}$$ |
| (B) | _27th_January_Evening_Shift_en_10_2.png) |
(II) | (i) $$\mathrm(NaOH)$$, (ii) $$\mathrm{CH_3Cl}$$ |
| (C) | _27th_January_Evening_Shift_en_10_3.png) |
(III) | (i) $$\mathrm{NaOH,CHCl_3}$$, (ii) $$\mathrm{NaOH}$$, (iii) $$\mathrm{HCl}$$ |
| (D) | _27th_January_Evening_Shift_en_10_4.png) |
(IV) | (i) $$\mathrm{NaOH}$$, (ii) $$\mathrm{CO_2}$$, (iii) $$\mathrm{HCl}$$ |
Choose the correct answer from the options given below :
$$\text { (A)-(II), (B)-(I), (C)-(III), (D)-(IV) }$$
$$\text { (A)-(IV), (B)-(I), (C)-(III), (D)-(II) }$$
$$\text { (A)-(IV), (B)-(III), (C)-(I), (D)-(II) }$$
$$\text { (A)-(II), (B)-(III), (C)-(I), (D)-(IV) }$$
Explanation
(A) $$\rightarrow$$ Kolbe Schmidt Reaction
(B) $$\rightarrow$$ Reimer Tiemann Reaction
(C) $$\rightarrow$$ Oxidation of phenol to p-benzoquinone
(D) $$\rightarrow \mathrm{PhOH}+\mathrm{NaOH} \rightarrow \mathrm{H}_2 \mathrm{O}+\mathrm{PhO}^{-}$$
_27th_January_Evening_Shift_en_10_5.png)
Comments (0)
