JEE MAIN - Chemistry (2024 - 1st February Evening Shift - No. 24)
The following data were obtained during the first order thermal decomposition of a gas A at constant volume :
$\mathrm{A}(\mathrm{g}) \rightarrow 2 \mathrm{~B}(\mathrm{~g})+\mathrm{C}(\mathrm{g})$
The rate constant of the reaction is ________ $\times 10^{-2} \mathrm{~s}^{-1}$ (nearest integer)
$\mathrm{A}(\mathrm{g}) \rightarrow 2 \mathrm{~B}(\mathrm{~g})+\mathrm{C}(\mathrm{g})$
S.No. | Time /s | Total pressure /(atm) |
---|---|---|
1. | 0 | 0.1 |
2. | 115 | 0.28 |
The rate constant of the reaction is ________ $\times 10^{-2} \mathrm{~s}^{-1}$ (nearest integer)
Answer
2
Explanation
_1st_February_Evening_Shift_en_24_1.png)
$\begin{aligned} & 0.1+2 \mathrm{x}=0.28 \\\\ & 2 \mathrm{x}=0.18 \\\\ & \mathrm{x}=0.09 \\\\ & \mathrm{~K}=\frac{1}{115} \ln \frac{0.1}{0.1-0.09} \\\\ & =0.0200 \mathrm{sec}^{-1} \\\\ & =2 \times 10^{-2} \mathrm{sec}^{-1}\end{aligned}$
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