JEE MAIN - Chemistry (2023 - 8th April Morning Shift - No. 9)
The major product formed in the following reaction is:
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Explanation
$\mathrm{NaBH}_4$ (Sodium borohydride) is a weak reducing agent, it reduces aldehydes/ketones but not esters, it produces alcohols through reduction. ketones reduces to $2^{\circ}$ alcohol.
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Note: Lithium borohydride is commonly used for selective reduction of esters and lactones to the corresponding alcohol.
_8th_April_Morning_Shift_en_9_6.png)
Note: Lithium borohydride is commonly used for selective reduction of esters and lactones to the corresponding alcohol.
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