JEE MAIN - Chemistry (2023 - 8th April Morning Shift - No. 6)
Match List I with List II:
_8th_April_Morning_Shift_en_6_1.png)
| LIST I (Reagent) | LIST II (Product) | ||
|---|---|---|---|
| A. | _8th_April_Morning_Shift_en_6_2.png) |
I. | _8th_April_Morning_Shift_en_6_3.png) |
| B. | $$\mathrm{HBF_4,\Delta}$$ | II. | _8th_April_Morning_Shift_en_6_4.png) |
| C. | $$\mathrm{Cu,HCl}$$ | III. | _8th_April_Morning_Shift_en_6_5.png) |
| D. | $$\mathrm{CuCN/KCN}$$ | IV. | _8th_April_Morning_Shift_en_6_6.png) |
Choose the correct answer from the options given below:
A-III, B-I, C-IV, D-II
A-III, B-I, C-II, D-IV
A-IV, B-III, C-II, D-I
A-I, B-III, C-IV, D-II
Explanation
(A) Coupling Reaction:
_8th_April_Morning_Shift_en_6_7.png)
(B) Balz-Schiemann reaction:
_8th_April_Morning_Shift_en_6_8.png)
(C) Gattermann Reaction $\rightarrow$ In this reaction, chlorine or bromine can be introduced in the benzene ring by treating the benzene diazonium salt solution with corresponding halogen acid in the presence of copper powder.
_8th_April_Morning_Shift_en_6_9.png)
(D) In the given reaction when benzene diazonium salt is treated with KCN and copper powder, it forms aryl nitrile or benzyl nitrile as a product.
_8th_April_Morning_Shift_en_6_10.png)
(B) Balz-Schiemann reaction:
(C) Gattermann Reaction $\rightarrow$ In this reaction, chlorine or bromine can be introduced in the benzene ring by treating the benzene diazonium salt solution with corresponding halogen acid in the presence of copper powder.
(D) In the given reaction when benzene diazonium salt is treated with KCN and copper powder, it forms aryl nitrile or benzyl nitrile as a product.
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