JEE MAIN - Chemistry (2023 - 8th April Morning Shift - No. 19)
When a $$60 \mathrm{~W}$$ electric heater is immersed in a gas for 100 s in a constant volume container with adiabatic walls, the temperature of the gas rises by $$5^{\circ} \mathrm{C}$$. The heat capacity of the given gas is ___________ $$\mathrm{J} \mathrm{K}^{-1}$$ (Nearest integer)
Answer
1200
Explanation
The heat provided by the heater is given by the equation:
$Q = \text{Power} \times \text{Time}$
Substituting the given values:
$Q = 60 \, \text{W} \times 100 \, \text{s} = 6000 \, \text{J}$
The heat capacity (C) is defined as the amount of heat required to raise the temperature of a substance by one degree. It is given by the equation:
$C = Q/\Delta T$
Substituting the given values:
$C = 6000 \, \text{J} / 5 \, \text{°C} = 1200 \, \text{J/K}$
So, the heat capacity of the given gas is approximately 1200 J/K.
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