JEE MAIN - Chemistry (2023 - 6th April Evening Shift - No. 3)
Consider the following reaction that goes from A to B in three steps as shown below:
_6th_April_Evening_Shift_en_3_1.png)
Choose the correct option
_6th_April_Evening_Shift_en_3_2.png)
_6th_April_Evening_Shift_en_3_3.png)
_6th_April_Evening_Shift_en_3_4.png)
_6th_April_Evening_Shift_en_3_5.png)
Explanation
Step with highest activation energy is RDS, so step II is RDS
No. of activated complex $=3$
_6th_April_Evening_Shift_en_3_6.png)
$\mathrm{P}$ and $\mathrm{Q}$ are intermediates
$($ Number of intermediates $=2$ )
No. of activated complex $=3$
$\mathrm{P}$ and $\mathrm{Q}$ are intermediates
$($ Number of intermediates $=2$ )
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