JEE MAIN - Chemistry (2023 - 31st January Morning Shift - No. 6)
The correct increasing order of the ionic radii is
$$\mathrm{Cl^- < Ca^{2+} < K^+ < S^{2-}}$$
$$\mathrm{K^+ < S^{2-} < Ca^{2+} < Cl^-}$$
$$\mathrm{Ca^{2+} < K^+ < Cl^- < S^{2-}}$$
$$\mathrm{S^{2-} < Cl^- < Ca^{2+} < K^+}$$
Explanation
In isoelectronic species size $\propto \frac{1}{Z}$
$$ \mathrm{Ca}^{2+}<\mathrm{K}^{+}<\mathrm{Cl}^{-}<\mathrm{S}^{2-} \text { : Size } $$
$\begin{array}{lllll}Z: & 20 & 19 & 17 & 18\end{array}$
$$ \mathrm{Ca}^{2+}<\mathrm{K}^{+}<\mathrm{Cl}^{-}<\mathrm{S}^{2-} \text { : Size } $$
$\begin{array}{lllll}Z: & 20 & 19 & 17 & 18\end{array}$
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