JEE MAIN - Chemistry (2023 - 31st January Evening Shift - No. 4)
An organic compound $[\mathrm{A}]\left(\mathrm{C}_{4} \mathrm{H}_{11} \mathrm{~N}\right)$, shows optical activity and gives $\mathrm{N}_{2}$ gas on treatment with $\mathrm{HNO}_{2}$. The compound $[\mathrm{A}]$ reacts with $\mathrm{PhSO}_{2} \mathrm{Cl}$ producing a compound which is soluble in $\mathrm{KOH}$. The structure of $\mathrm{A}$ is :
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Explanation
Only primary amines react with PhSO2Cl to
produce a compounds which are soluble in KOH.
Option (B) and (D) are primary amines but the given compound is also optically active.
Hence the correct answer is (B).
Option (B) and (D) are primary amines but the given compound is also optically active.
Hence the correct answer is (B).
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