JEE MAIN - Chemistry (2023 - 30th January Morning Shift - No. 8)
During the qualitative analysis of $$\mathrm{SO}_{3}^{2-}$$ using dilute $$\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{SO}_{2}$$ gas is evolved which turns $$\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$$ solution (acidified with dilute $$\mathrm{H}_{2} \mathrm{SO}_{4}$$) :
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black
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green
Explanation
$$\mathrm{S{O_2} + C{r_2}O_7^{2 - }\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{}} \mathop {C{r^{3 + }}}\limits_{(green)} + SO_4^{2 - }}$$
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