JEE MAIN - Chemistry (2023 - 30th January Morning Shift - No. 21)
A solution containing $$2 \mathrm{~g}$$ of a non-volatile solute in $$20 \mathrm{~g}$$ of water boils at $$373.52 \mathrm{~K}$$. The molecular mass of the solute is ___________ $$\mathrm{g} ~\mathrm{mol}^{-1}$$. (Nearest integer)
Given, water boils at $$373 \mathrm{~K}, \mathrm{~K}_{\mathrm{b}}$$ for water $$=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$$
Answer
100
Explanation
$$\mathrm{\Delta T_b=K_b.m}$$
(0.52) = (0.52) (m)
$$\mathrm{m=1=\frac{2(1000)}{(mw)(20)}}$$
mw = 100
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