JEE MAIN - Chemistry (2023 - 30th January Morning Shift - No. 16)
$$600 \mathrm{~mL}$$ of $$0.01~\mathrm{M} ~\mathrm{HCl}$$ is mixed with $$400 \mathrm{~mL}$$ of $$0.01~\mathrm{M} ~\mathrm{H}_{2} \mathrm{SO}_{4}$$. The $$\mathrm{pH}$$ of the mixture is ___________ $$\times 10^{-2}$$. (Nearest integer)
[Given $$\log 2=0.30$$
$$\log 3=0.48$$
$$\log 5=0.69$$
$$\log 7=0.84$$
$$\log 11=1.04]$$
Answer
186
Explanation
$$\mathrm{[H^+]=\frac{6+8}{1000}=14\times10^{-3}}$$
$$\mathrm{pH=3-\log14}$$
$$=3-.3-.84$$
$$=1.86=186\times10^{-2}$$
Comments (0)
