JEE MAIN - Chemistry (2023 - 30th January Morning Shift - No. 10)
Match List I with List II
| List I | List II | ||
|---|---|---|---|
| A. | _30th_January_Morning_Shift_en_10_1.png) |
I. | Fittig reaction |
| B. | _30th_January_Morning_Shift_en_10_2.png) |
II. | Wurtz Fittig reaction |
| C. | _30th_January_Morning_Shift_en_10_3.png) |
III. | Finkelstein reaction |
| D. | $$\mathrm{C_5H_5C1+NaI\to C_2H_5I+NaCl}$$ | IV. | Sandemyer reaction |
Choose the correct answer from the options given below :
A - IV, B - II, C - III, D - I
A - II, B - I, C - IV, D - III
A - II, B - I, C - III, D - IV
A - III, B - II, C - IV, D - I
Explanation
_30th_January_Morning_Shift_en_10_4.png)
_30th_January_Morning_Shift_en_10_5.png)
_30th_January_Morning_Shift_en_10_6.png)
(D) $$\mathrm{C_2H_5Cl+Nal\longrightarrow C_2H_5l+NaCl}$$ (Finkelstein reaction)
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