JEE MAIN - Chemistry (2023 - 29th January Morning Shift - No. 8)
Match List I with List II
| List I | List II | ||
|---|---|---|---|
| Reaction | Reagents | ||
| (A) | Hoffmann Degradation | (I) | $$\mathrm{Conc. KOH}$$, $$\Delta$$ |
| (B) | Clemenson reduction | (II) | $$\mathrm{CHCl_3,NaOH/H_3O}$$$$^ \oplus $$ |
| (C) | Cannizaro reaction | (III) | $$\mathrm{Br_2,NaOH}$$ |
| (D) | Reimer-Tiemann Reaction | (IV) | $$\mathrm{Zn-Hg/HCl}$$ |
Choose the correct answer from the options given below :
(A) - III, (B) - IV, (C) - I, (D) - II
(A) - II, (B) - IV, (C) - I, (D) - III
(A) - III, (B) - IV, (C) - II, (D) - I
(A) - II, (B) - I, (C) - III, (D) - IV
Explanation
| Reaction | Reagents | ||
|---|---|---|---|
| (A) | $\begin{aligned} & \text { Hoffmann } \\ & \text { degradation }\end{aligned}$ | $\longrightarrow$ | $\mathrm{Br}_{2}, \mathrm{NaOH}$ |
| (B) | $\begin{aligned} & \text { Clemenson } \\ & \text { reduction }\end{aligned}$ | $\longrightarrow$ | $\mathrm{Zn}-\mathrm{Hg} / \mathrm{HCl}$ |
| (C) | $\begin{aligned} & \text { Cannizaro- } \\ & \text { reaction }\end{aligned}$ | $\longrightarrow$ | Conc. $\mathrm{KOH}, \Delta$ |
| (D) | $\begin{aligned} & \text { Reimer-Tiemann } \\ & \text { reaction }\end{aligned}$ | $\longrightarrow$ | $\begin{aligned} & \mathrm{CHCl}_{3}, \\ & \mathrm{NaOH} / \mathrm{H}_{3} \mathrm{O}^{+}\end{aligned}$ |
$\therefore$ Correct match is : (A)-III, (B) -IV, (C) -I, (D)-II
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