JEE MAIN - Chemistry (2023 - 29th January Morning Shift - No. 12)
Following chromatogram was developed by adsorption of compound 'A' on a 6 cm TLC glass plate. Retardation factor of the compound 'A' is _________ $$\times 10^{-1}$$.
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Answer
6
Explanation
$\mathrm{R}_{\mathrm{f}}=\frac{\text { Distance moved by thesubstance frombaseline }}{\text { Distance moved by thesolvent frombaseline }}$
$=\frac{3.0 \mathrm{~cm}}{5.0 \mathrm{~cm}}=0.6$ or $6 \times 10^{-1}$
$=\frac{3.0 \mathrm{~cm}}{5.0 \mathrm{~cm}}=0.6$ or $6 \times 10^{-1}$
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